integral from-2 to 0 of x^2-4

Lösung

\int_{- 2}^{0} x^{2} - 4 d x

- \frac{16}{3}

Dezimale

- 5.33333 \dots

Schritte zur Lösung

\int_{- 2}^{0} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} x^{2} d x - \int_{- 2}^{0} 4 d x

\int_{- 2}^{0} x^{2} d x = \frac{8}{3}

\int_{- 2}^{0} 4 d x = 8

= \frac{8}{3} - 8

Vereinfache

\frac{8}{3} - 8 : - \frac{16}{3}

= - \frac{16}{3}

\int_{1}^{2} x^{4} ln (3 x) d x

\int_{0}^{3} (3 - x^{2}) d x

\int_{- 3}^{- 1} 2 x + 6 d x

\int_{x}^{\infty} e^{- y^{2}} d y

\int_{0}^{1} (2 x^{3} - 5 x + 9) d x