integral from 0 to 12 of 1/(1+x^2)

Lösung

\int_{0}^{12} \frac{1}{1 + x ^{2}} d x

arctan (12)

Dezimale

1.48765 \dots

Schritte zur Lösung

\int_{0}^{12} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{12}

Berechne die Grenzen:

arctan (12)

= arctan (12)

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