integral from 1 to 3 of x^3+x+6

Lösung

\int_{1}^{3} x^{3} + x + 6 d x

36

Schritte zur Lösung

\int_{1}^{3} x^{3} + x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{3} d x + \int_{1}^{3} x d x + \int_{1}^{3} 6 d x

\int_{1}^{3} x^{3} d x = 20

\int_{1}^{3} x d x = 4

\int_{1}^{3} 6 d x = 12

= 20 + 4 + 12

Vereinfache

= 36

\int_{0}^{π} cos (x) + 1 d x

\int_{0}^{2 π} \frac{1}{4} sin^{2} (x) d x

\int_{0}^{2} (x - 2)^{3} d x

\int_{0}^{π} 2 π (sin (x)) d x

\int_{y}^{y + 1} 2 y d y