integral from-1 to 1 of (4x^2+1)

Lösung

\int_{- 1}^{1} (4 x^{2} + 1) d x

\frac{14}{3}

Dezimale

4.66666 \dots

Schritte zur Lösung

\int_{- 1}^{1} 4 x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 4 x^{2} d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 4 x^{2} d x = \frac{8}{3}

\int_{- 1}^{1} 1 d x = 2

= \frac{8}{3} + 2

Vereinfache

\frac{8}{3} + 2 : \frac{14}{3}

= \frac{14}{3}

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