integral from 4 to 5 of 1/2 (5-x)

Lösung

\int_{4}^{5} \frac{1}{2} (5 - x) d x

\frac{1}{4}

Dezimale

0.25

Schritte zur Lösung

\int_{4}^{5} \frac{1}{2} (5 - x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{4}^{5} 5 - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{4}^{5} 5 d x - \int_{4}^{5} x d x)

\int_{4}^{5} 5 d x = 5

\int_{4}^{5} x d x = \frac{9}{2}

= \frac{1}{2} (5 - \frac{9}{2})

Vereinfache

\frac{1}{2} (5 - \frac{9}{2}) : \frac{1}{4}

= \frac{1}{4}

\int_{0}^{4} \frac{1}{2 x + 1} d x

\int_{1}^{4} \frac{1}{4 x + 9} d x

\int_{0}^{5} \frac{1}{2} x^{2} d x

\int_{0}^{3} (e^{2 x} + x^{3}) d x

\int_{0}^{1} v 1 - v^{2} d v