e^{2x}(2cos(y)dx-sin(y)dy)=0

Lösung

e^{2 x} (2 cos (y) d x - sin (y) d y) = 0

y = arccos (e^{- 2 x - c_{1}}) + 2 πn, y = - arccos (e^{- 2 x - c_{1}}) + 2 πn

Schritte zur Lösung

e^{2 x} (2 cos (y) d x - sin (y) d y) = 0

Solve separable ODE:

y = arccos (e^{- 2 x - c_{1}}) + 2 πn, y = - arccos (e^{- 2 x - c_{1}}) + 2 πn

y = arccos (e^{- 2 x - c_{1}}) + 2 πn, y = - arccos (e^{- 2 x - c_{1}}) + 2 πn

3 (1 + t^{2}) y^{^{'}} = 2 t y (y^{3} - 1)

\frac{d y}{d x} = 2 x y - x

\frac{d y}{d x} = - 0.01 y

\frac{d y}{d t} + 2 t y = t

(x^{2} y - 2 x y) d x + 3 x y^{2} d y = 0