(dy)/(5x+2)-(dx)/(2y-1)=0

解

\frac{d y}{5 x + 2} - \frac{d x}{2 y - 1} = 0

y = \frac{1 + - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}, y = \frac{1 - - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}

解答ステップ

\frac{d y}{5 x + 2} - \frac{d x}{2 y - 1} = 0

分離可能 ODE を解く:

y = \frac{1 + - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}, y = \frac{1 - - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}

y = \frac{1 + - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}, y = \frac{1 - - 2 ( - 5 x ^{2} - 4 x - c _{1} ) + 1}{2}