2sin(y^2)dx+xycos(y^2)dy=0

Lösung

2 sin (y^{2}) d x + x y cos (y^{2}) d y = 0

y = arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn, y = - π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn

Schritte zur Lösung

2 sin (y^{2}) d x + x y cos (y^{2}) d y = 0

Solve separable ODE:

y = arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn, y = - π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn

y = arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arcsin (\frac{c _{1}}{x ^{4}}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn, y = - π + arcsin (- \frac{c _{1}}{x ^{4}}) + 2 πn

\frac{d v}{d t} + 2 v = 9, v (0) = 0

y^{^{'}} = \frac{x y}{x ^{2} + 1}

f^{^{'}} (x) + f (x) = 3

y^{^{'}} = - 5 x y^{2}

y^{^{'}} - 3 x y = - y