(dy)/(dx)-0.2xy=0,y(1)=1

解答

\frac{d y}{d x} - 0.2 x y = 0, y (1) = 1

y = e^{0.1 x^{2} - 0.1}

求解步骤

\frac{d y}{d x} - 0.2 x y = 0

求解可分离方程:

y = e^{0.1 x^{2} - 0.1}

y = e^{0.1 x^{2} - 0.1}

\frac{d y}{d t} = 0.125 (y - 3), y (0) = 5

\frac{d y}{d x} = 2 y - 6

y y^{^{'}} = sin (x) + cos (x)

y^{^{'}} = y sin (x)

y y^{^{'}} = x - x^{2}, y (0) = x 1 - x^{2}