yy^'=xe^{y^2}

Lösung

y y^{^{'}} = x e^{y^{2}}

y = - ln (- x^{2} - c_{1}), y = - - ln (- x^{2} - c_{1})

Schritte zur Lösung

y y^{'} (x) = x e^{y^{2}}

Solve separable ODE:

y = - ln (- x^{2} - c_{1}), y = - - ln (- x^{2} - c_{1})

y = - ln (- x^{2} - c_{1}), y = - - ln (- x^{2} - c_{1})

y^{^{'}} - x y = 0

\frac{d y}{d x} = \frac{2 y}{( x + 1 ) + ( x + 1 ) ^{\frac{5}{2}}}

\frac{d y}{d x} = \frac{cos ( x )}{2 y}

- y = k \frac{d y}{d x}

e^{2 t} y^{^{'}} = y^{2}