y^'+18xy=0

Lösung

y^{^{'}} + 18 x y = 0

y = e^{- 9 x^{2} + c_{1}}

Schritte zur Lösung

y^{'} (x) + 18 x y = 0

Solve separable ODE:

y = e^{- 9 x^{2} + c_{1}}

y = e^{- 9 x^{2} + c_{1}}

x^{^{'}} + a x = b

x^{^{'}} = 1 - 2.2 x

y^{^{'}} = 4 x^{3} y^{4}

\frac{d y}{d x} = 6 x^{4} y, y > 0

\frac{d y}{d x} - 2 y^{2} cos^{2} (x) = 3 x^{2} y^{2}