y^'=-xy+(4x)/y

Lösung

y^{^{'}} = - x y + \frac{4 x}{y}

y = e^{- x^{2} - c_{1}} + 4, y = - e^{- x^{2} - c_{1}} + 4

Schritte zur Lösung

y^{'} (x) = - x y + \frac{4 x}{y}

Solve separable ODE:

y = e^{- x^{2} - c_{1}} + 4, y = - e^{- x^{2} - c_{1}} + 4

y = e^{- x^{2} - c_{1}} + 4, y = - e^{- x^{2} - c_{1}} + 4

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 0, y (0) = 3

\frac{d y}{y + 2} = d x

\frac{d x}{x} = \frac{d z}{z}

\frac{d y}{d x} + b y - a = 0

d x + (\frac{y - 1}{x ^{2}})^{3} d y = 0