y^'=2x^3*y^2

Lösung

y^{^{'}} = 2 x^{3} \cdot y^{2}

y = - \frac{2}{x ^{4} + c _{1}}

Schritte zur Lösung

y^{'} (x) = 2 x^{3} \cdot y^{2}

Solve separable ODE:

y = - \frac{2}{x ^{4} + c _{1}}

y = - \frac{2}{x ^{4} + c _{1}}

- y^{^{'}} - 9 y = 0

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 9

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 8

x d z + z d x = \frac{x ^{2} - x ^{2} z ^{2}}{3 x ^{2} z}

y^{^{'}} = 4 x (1 + y)^{2}