y^'=(3+sin(t))y^2

Lösung

y^{^{'}} = (3 + sin (t)) y^{2}

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

Schritte zur Lösung

y^{'} (t) = (3 + sin (t)) y^{2}

Solve separable ODE:

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

y = - \frac{1}{3 t - cos ( t ) + c _{1}}

y^{^{'}} = - x^{2} \cdot (y)^{2}

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{3}

d y (y + x^{2} y) = 2 x d x

y^{^{'}} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}, y (0) = - 1

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{2}