1/(3y^')=(2x+1)/(6y)

Lösung

\frac{1}{3 y ^{^{'}}} = \frac{2 x + 1}{6 y}

y = 2 e^{c_{1}} x + e^{c_{1}}

Schritte zur Lösung

\frac{1}{3 y ^{'} ( x )} = \frac{2 x + 1}{6 y}

Solve separable ODE:

y = 2 e^{c_{1}} x + e^{c_{1}}

y = 2 e^{c_{1}} x + e^{c_{1}}

y^{^{'}} + 10 y = 0

x (\frac{d y}{d x}) = 6 y

y^{^{'}} + k^{2} y = 0

(1 + x^{3}) \frac{d y}{d x} = x^{2} y

\frac{d y}{d x} = \frac{x ( 3 + y ^{2} )}{y ( 2 + x ^{2} )}