y^'=0.8(y-250)

Lösung

y^{^{'}} = 0.8 (y - 250)

y = e^{0.8 t + c_{1}} + 250

Schritte zur Lösung

y^{'} (t) = 0.8 (y - 250)

Solve separable ODE:

y = e^{0.8 t + c_{1}} + 250

y = e^{0.8 t + c_{1}} + 250

3 y^{^{'}} - 6 y = 1

y = x^{10} \frac{d y}{d x}

2 x y - \frac{d y}{d x} - x = 0

\frac{d x}{d t} + \frac{3}{100} x = 0.8

y^{^{'}} - e^{3 x + 2 y} = 0