1/x y^'-y-1=0

Lösung

\frac{1}{x} y^{^{'}} - y - 1 = 0

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Schritte zur Lösung

\frac{1}{x} y^{'} (x) - y - 1 = 0

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y^{^{'}} - 2 y = 10, y (0) = 0

y^{2} sec (4 x) \frac{d y}{d x} = 1, y (0) = 0

y^{^{'}} = \frac{x + x y}{1 + x ^{2}}

\frac{d y}{d x} x^{2} + 2 x^{2} y + 3 x y = 0

\frac{d x}{d t} = 20 - 0.4 x