8yy^'=x,y(8)=6

Lösung

8 y y^{^{'}} = x, y (8) = 6

y = \frac{224 + x ^{2}}{2 2}

Schritte zur Lösung

8 y y^{'} (x) = x

Solve separable ODE:

y = \frac{224 + x ^{2}}{2 2}

y = \frac{224 + x ^{2}}{2 2}

y^{^{'}} = t (3 - 2 y)

\frac{d x}{d t} = r x (1 - \frac{x}{2})

y^{^{'}} + tan (5 \cdot x) y = 0

(3 y^{2} - 8 x^{- 1} y) d x + (3 x y - 8) d y = 0

cos (8 y) d y = - sin (2 x) d x