y^'+cos(t)y=cos(t)

Lösung

y^{^{'}} + cos (t) y = cos (t)

y = e^{- s i n (t) + c_{1}} + 1

Schritte zur Lösung

y^{'} (t) + cos (t) y = cos (t)

Solve separable ODE:

y = e^{- s i n (t) + c_{1}} + 1

y = e^{- s i n (t) + c_{1}} + 1

\frac{d y}{d x} = \frac{x}{2 y x + y}

y^{^{'}} = \frac{2 x + x y ^{2}}{4 y + x ^{2} y}

y^{^{'}} = 5 y - 4

y^{^{'}} = 5 y - 3

\frac{d y}{d x} = \frac{y + 1}{x + 1}