y^'-3e^{5x-2y}=0

Lösung

y^{^{'}} - 3 e^{5 x - 2 y} = 0

y = \frac{ln ( \frac{6}{5} e ^{5 x} + c _{1} )}{2}

Schritte zur Lösung

y^{'} (x) - 3 e^{5 x - 2 y} = 0

Solve separable ODE:

y = \frac{ln ( \frac{6}{5} e ^{5 x} + c _{1} )}{2}

y = \frac{ln ( \frac{6}{5} e ^{5 x} + c _{1} )}{2}

y^{^{'}} = - 9 x^{2} y

y^{^{'}} = 2 y - 1, y (0) = 1

\frac{d}{d x} ((p) x^{3}) + p (x)^{2} = 108

(x - 1) \frac{d y}{d x} = (4 - y^{2})

y^{^{'}} = 1 + 5 y