-y^'=-2yy

Lösung

- y^{^{'}} = - 2 yy

y = - \frac{1}{2 t + c _{1}}

Schritte zur Lösung

- y^{'} (t) = - 2 yy

Solve separable ODE:

y = - \frac{1}{2 t + c _{1}}

y = - \frac{1}{2 t + c _{1}}

y^{^{'}} - 6 y = 12, y (0) = 0

(3 x - 3) \cdot (\frac{d y}{d x}) + 3 y + 5 = 0

\frac{d y}{d x} y = arctan (8) x^{3}

\frac{d v}{d x} = 3 v

y^{^{'}} - x^{3} e^{- y} = 0