integral from 3 to 5 of 1/((x-4)^2)

解答

\int_{3}^{5} \frac{1}{( x - 4 ) ^{2}} d x

发散

求解步骤

\int_{3}^{5} \frac{1}{( x - 4 ) ^{2}} d x

找到无定义的点（奇点）:

x = 4

如果存在

b, a < b < c, f (b) =

无定义

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{3}^{4} \frac{1}{( x - 4 ) ^{2}} d x + \int_{4}^{5} \frac{1}{( x - 4 ) ^{2}} d x

\int_{3}^{4} \frac{1}{( x - 4 ) ^{2}} d x =

发散

如果表达式有部分发散，则整个表达式发散

= 发散

\frac{\partial}{\partial x} (\frac{x - 3 y}{2 x y + 3})

\frac{\partial}{\partial x} (3 - 3 x + 4 y - 4 x^{2} y)

\frac{d}{d x} (\frac{45}{0.01 x ^{2} + 1})

\int 3 cos (10 x) d x

\frac{d}{d x} (lo g_{5} (x^{4} 2 x^{2} + 9 x))