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Beliebt Rechnen >

y^{''}+9y=sin(2x),y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + 9 y = sin (2 x), y (0) = 0, y^{^{'}} (0) = 0

Lösung

y = - \frac{2}{15} sin (3 x) + \frac{1}{5} sin (2 x)

Schritte zur Lösung

y^{''} (x) + 9 y = sin (2 x)

Solve linear ODE:

y = - \frac{2}{15} sin (3 x) + \frac{1}{5} sin (2 x)

y = - \frac{2}{15} sin (3 x) + \frac{1}{5} sin (2 x)

Graph

Beliebte Beispiele

y^{''}+4y=8sin(2x)+5e^x

y^{^{''}} + 4 y = 8 sin (2 x) + 5 e^{x}

y^{''}-y^'-6y=-e^x+12x,y(0)=1,y^'(0)=-2

y^{^{''}} - y^{^{'}} - 6 y = - e^{x} + 12 x, y (0) = 1, y^{^{'}} (0) = - 2

y^{''}+25y=82e^{4x}

y^{^{''}} + 25 y = 82 e^{4 x}

y^{''}-4y^'+4y=-3e^{2x}+(e^{2x})/x

y^{^{''}} - 4 y^{^{'}} + 4 y = - 3 e^{2 x} + \frac{e ^{2 x}}{x}

y^{''}+8y^'+12y=1-\H(t-3)

y^{^{''}} + 8 y^{^{'}} + 12 y = 1 - H (t - 3)