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Beliebt Rechnen >

2y^{''}+27y=e^t-e^{-t},y(0)=0,y^'(0)=2

Lösung

2 y^{^{''}} + 27 y = e^{t} - e^{- t}, y (0) = 0, y^{^{'}} (0) = 2

Lösung

y = \frac{e ^{t} - e ^{- t}}{29} + \frac{56 2}{87 3} sin (\frac{3 3 t}{2})

Schritte zur Lösung

2 y^{''} (t) + 27 y = e^{t} - e^{- t}

Solve linear ODE:

y = \frac{e ^{t} - e ^{- t}}{29} + \frac{56 2}{87 3} sin (\frac{3 3 t}{2})

y = \frac{e ^{t} - e ^{- t}}{29} + \frac{56 2}{87 3} sin (\frac{3 3 t}{2})

Graph

Beliebte Beispiele

y^{''}-y^'+2y=6e^{1/2}

y^{^{''}} - y^{^{'}} + 2 y = 6 e^{\frac{1}{2}}

y^{''}+16y=2csc^2(4x)

y^{^{''}} + 16 y = 2 csc^{2} (4 x)

y^{''}+5y^'+6y=sin(x)-cos(2x)

y^{^{''}} + 5 y^{^{'}} + 6 y = sin (x) - cos (2 x)

y^{''}-10y^'+25=e^{5x}ln(4+x^2)

y^{^{''}} - 10 y^{^{'}} + 25 = e^{5 x} ln (4 + x^{2})

y^{^{''}} + y = 4 x^{2}