y^{''}+16y=13sec^2(4t)

Lösung

y^{^{''}} + 16 y = 13 sec^{2} (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 13 + 13 ln ( tan ( 4 t ) + sec ( 4 t ) ) sin ( 4 t )}{16}

Schritte zur Lösung

y^{''} (t) + 16 y = 13 sec^{2} (4 t)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 13 + 13 ln ( tan ( 4 t ) + sec ( 4 t ) ) sin ( 4 t )}{16}

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 13 + 13 ln ( tan ( 4 t ) + sec ( 4 t ) ) sin ( 4 t )}{16}

y^{^{''}} + 7 y^{^{'}} - y = 16

9 y^{^{''}} - 4 y = sin (t)

y^{^{''}} + y = 8 cos (x)

y^{^{''}} - y^{^{'}} - 2 y = 6 x + 6

y^{^{''}} + y^{^{'}} = 8