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Beliebt Rechnen >

y^{''}+5y^'+4x=0

Lösung

y^{^{''}} + 5 y^{^{'}} + 4 x = 0

Lösung

y = c_{1} + c_{2} e^{- 5 x} - \frac{2 x ^{2}}{5} + \frac{4 x}{25}

Schritte zur Lösung

y^{''} (x) + 5 y^{'} (x) + 4 x = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 x} - \frac{2 x ^{2}}{5} + \frac{4 x}{25}

y = c_{1} + c_{2} e^{- 5 x} - \frac{2 x ^{2}}{5} + \frac{4 x}{25}

Graph

Beliebte Beispiele

y^{''}+25y=25,y(0)=1,y^'(0)=-5

y^{^{''}} + 25 y = 25, y (0) = 1, y^{^{'}} (0) = - 5

2y^{''}+20y^'+50y=10sin(3x)

2 y^{^{''}} + 20 y^{^{'}} + 50 y = 10 sin (3 x)

y^{'''}-y^'=3x+4e^x+5e^{2x}

y^{^{'''}} - y^{^{'}} = 3 x + 4 e^{x} + 5 e^{2 x}

y^{'''}-19y^'+30y=x^2*e^{2x}

y^{^{'''}} - 19 y^{^{'}} + 30 y = x^{2} \cdot e^{2 x}

y^{''}-4y^'-5y=125,y(0)=0,y^'(0)=0

y^{^{''}} - 4 y^{^{'}} - 5 y = 125, y (0) = 0, y^{^{'}} (0) = 0