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Beliebt Rechnen >

x''+2x=8,x(pi)=0,x(0)=0

Lösung

x^{^{''}} + 2 x = 8, x (π) = 0, x (0) = 0

Lösung

x = - 4 cos (2 t) - \frac{( - 4 cos ( 2 π ) + 4 ) sin ( 2 t )}{sin ( 2 π )} + 4

Schritte zur Lösung

x^{''} (t) + 2 x = 8

Solve linear ODE:

x = - 4 cos (2 t) - \frac{( - 4 cos ( 2 π ) + 4 ) sin ( 2 t )}{sin ( 2 π )} + 4

x = - 4 cos (2 t) - \frac{( - 4 cos ( 2 π ) + 4 ) sin ( 2 t )}{sin ( 2 π )} + 4

Beliebte Beispiele

y^{''}-y^'-42y=-122t+84t^2

y^{^{''}} - y^{^{'}} - 42 y = - 122 t + 84 t^{2}

(d^2y)/(dt^2)+12(dy)/(dt)+36y=-4t+3

\frac{d ^{2} y}{d t ^{2}} + 12 \frac{d y}{d t} + 36 y = - 4 t + 3

y^{''}-2y^'=4x+e^x

y^{^{''}} - 2 y^{^{'}} = 4 x + e^{x}

y^{''}+2y^'=cos(t),y(0)=0

y^{^{''}} + 2 y^{^{'}} = cos (t), y (0) = 0

y^{''}+7y^'=cos(2x)+8e^{-5x}

y^{^{''}} + 7 y^{^{'}} = cos (2 x) + 8 e^{- 5 x}