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Beliebt Rechnen >

0.75y^{''}+50y=5t^2

Lösung

0.75 y^{^{''}} + 50 y = 5 t^{2}

Lösung

y = c_{1} cos (\frac{10 2 t}{3}) + c_{2} sin (\frac{10 2 t}{3}) + \frac{t ^{2}}{10} - 0.003

Schritte zur Lösung

0.75 y^{''} (t) + 50 y = 5 t^{2}

Solve linear ODE:

y = c_{1} cos (\frac{10 2 t}{3}) + c_{2} sin (\frac{10 2 t}{3}) + \frac{t ^{2}}{10} - 0.003

y = c_{1} cos (\frac{10 2 t}{3}) + c_{2} sin (\frac{10 2 t}{3}) + \frac{t ^{2}}{10} - 0.003

Graph

Beliebte Beispiele

(D^2-5D+6)y=x^2e^{3x}

(D^{2} - 5 D + 6) y = x^{2} e^{3 x}

y^{''}+10y^'+20y=50sinh(5x)

y^{^{''}} + 10 y^{^{'}} + 20 y = 50 sinh (5 x)

(d^4y)/(dx^4)+3(d^2y)/(dx^2)-4=0

\frac{d ^{4} y}{d x ^{4}} + 3 \frac{d ^{2} y}{d x ^{2}} - 4 = 0

y^{''}-y^'=x+sin(x)

y^{^{''}} - y^{^{'}} = x + sin (x)

y^{''}+17y=5e^x

y^{^{''}} + 17 y = 5 e^{x}