y^{''}-2y^'+y=0,y(0)=-1,y(1)=2

Lösung

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = - 1, y (1) = 2

y = - e^{t} + (2 + e) e^{t - 1} t

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + y = 0

Solve linear ODE:

y = - e^{t} + (2 + e) e^{t - 1} t

y = - e^{t} + (2 + e) e^{t - 1} t

(D^{5} - D^{3}) y = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 4

y^{^{''}} - 9 y^{^{'}} + 20 y = 0, y (0) = 3, y^{^{'}} (0) = 2

y^{^{''}} + \frac{1}{100} y^{^{'}} = 0

x^{^{''}} - 7 x^{^{'}} + 12 = 12, x (0) = 5, x^{^{'}} (0) = 5