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Beliebt Rechnen >

2y^{''}+8y=0,y^'(0)=1,y(0)=0

Lösung

2 y^{^{''}} + 8 y = 0, y^{^{'}} (0) = 1, y (0) = 0

Lösung

y = \frac{1}{2} sin (2 t)

Schritte zur Lösung

2 y^{''} (t) + 8 y = 0

Solve linear ODE:

y = \frac{1}{2} sin (2 t)

y = \frac{1}{2} sin (2 t)

Graph

Beliebte Beispiele

(D^4-2D^3-3D^2+4D+4)y=0

(D^{4} - 2 D^{3} - 3 D^{2} + 4 D + 4) y = 0

40y^{''}+7y^'-3y=0

40 y^{^{''}} + 7 y^{^{'}} - 3 y = 0

y^{^{''}} + k^{2} \cdot y = 0

linear y^{''}=y

l in e a r y^{^{''}} = y

y^{''}-7y^'-8y=0,y(0)=1,y^'(0)=-1

y^{^{''}} - 7 y^{^{'}} - 8 y = 0, y (0) = 1, y^{^{'}} (0) = - 1