y^{''}+0.46y^'+128y=0

Lösung

y^{^{''}} + 0.46 y^{^{'}} + 128 y = 0

y = e^{- \frac{23 t}{100}} (c_{1} cos (\frac{1279471 t}{100}) + c_{2} sin (\frac{1279471 t}{100}))

Schritte zur Lösung

y^{''} (t) + 0.46 y^{'} (t) + 128 y = 0

Solve linear ODE:

y = e^{- \frac{23 t}{100}} (c_{1} cos (\frac{1279471 t}{100}) + c_{2} sin (\frac{1279471 t}{100}))

y = e^{- \frac{23 t}{100}} (c_{1} cos (\frac{1279471 t}{100}) + c_{2} sin (\frac{1279471 t}{100}))

2 y^{^{''}} - 4 y = 0

f^{^{''}} (t) + 2 f^{^{'}} (t) + 5 f (t) = 0, f (0) = 3, f^{^{'}} (0) = - 7

y^{^{'}} - y^{^{''}} - 4 y^{^{'}} + 4 y = 0

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = - 1, y^{^{'}} (0) = 2

\frac{d ^{2} x}{d t ^{2}} - 6 \frac{d x}{d t} + 9 x = 0