y^'=(x^8-8y)/x

Lösung

y^{^{'}} = \frac{x ^{8} - 8 y}{x}

y = \frac{x ^{8}}{16} + \frac{c _{1}}{x ^{8}}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{8} - 8 y}{x}

Solve linear ODE:

y = \frac{x ^{8}}{16} + \frac{c _{1}}{x ^{8}}

y = \frac{x ^{8}}{16} + \frac{c _{1}}{x ^{8}}

x \frac{d y}{d x} + 2 y = - 3 sin (x)

y^{^{''}} + 2 y^{^{'}} + 5 y = 10

x \to 4 lim (\frac{x ^{2} - 9}{x - 3})

a re a \frac{sec ^{2} ( x )}{2}, 2 cos^{2} (x)

x \to 0 lim (\frac{1}{5 + 5})