integral of 0.8x

解答

\int 0.8 x d x

0.4 x^{2} + C

求解步骤

\int 0.8 x d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.8 \cdot \int x d x

使用幂法则

= 0.8 \cdot \frac{x ^{2}}{2}

化简

0.8 \cdot \frac{x ^{2}}{2} : 0.4 x^{2}

= 0.4 x^{2}

解答补常数

= 0.4 x^{2} + C

\frac{\partial}{\partial y} (x^{2} + (y - 1)^{2} + z^{2})

\int_{1}^{9} \frac{x ^{2} - 1}{x} d x

\int \frac{5 x ^{2} - 10 x}{4 3 x ^{3}} d x

d er i v a t i v e 1 - 49 x^{2} arccos (7 x)

x \to 2 lim (7 (x) + 10)