derivative of (x+1/(\sqrt[3]{x})^2)

Lösung

\frac{d}{d x} ((x + \frac{1}{3 x})^{2})

2 (x + \frac{1}{3 x}) (1 - \frac{1}{3 x ^{\frac{4}{3}}})

Schritte zur Lösung

\frac{d}{d x} ((x + \frac{1}{3 x})^{2})

Wende die Kettenregel an:

2 (x + \frac{1}{3 x}) \frac{d}{d x} (x + \frac{1}{3 x})

= 2 (x + \frac{1}{3 x}) \frac{d}{d x} (x + \frac{1}{3 x})

\frac{d}{d x} (x + \frac{1}{3 x}) = 1 - \frac{1}{3 x ^{\frac{4}{3}}}

= 2 (x + \frac{1}{3 x}) (1 - \frac{1}{3 x ^{\frac{4}{3}}})

d er i v a t i v e a^{2} x^{2} + b^{2}

d er i v a t i v e y = (\frac{( x ^{2} + 8 )}{x ^{2} - 8})

d er i v a t i v e \frac{1}{( 1 - t ^{2} ) ^{\frac{1}{2}}}

t an g e n t f (x) = (\frac{x + 1}{x + 3})^{2}, at x = - 2

\int_{0}^{\infty} \frac{( y e ^{- \frac{y}{a}} )}{a} d y