derivative (3x-9)/(2x+8)

Lösung

ableitung von

\frac{3 x - 9}{2 x + 8}

\frac{21}{2 ( x + 4 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{3 x - 9}{2 x + 8})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 9 ) ( 2 x + 8 ) - \frac{d}{d x} ( 2 x + 8 ) ( 3 x - 9 )}{( 2 x + 8 ) ^{2}}

\frac{d}{d x} (3 x - 9) = 3

\frac{d}{d x} (2 x + 8) = 2

= \frac{3 ( 2 x + 8 ) - 2 ( 3 x - 9 )}{( 2 x + 8 ) ^{2}}

Vereinfache

\frac{3 ( 2 x + 8 ) - 2 ( 3 x - 9 )}{( 2 x + 8 ) ^{2}} : \frac{21}{2 ( x + 4 ) ^{2}}

= \frac{21}{2 ( x + 4 ) ^{2}}

d er i v a t i v e t^{- 3}

x \to - 2 lim (\frac{1}{2 - x})

\frac{d}{d x} (2 sin (x) - 2 x cos (x))

\frac{\partial}{\partial x} (ln (1 + x^{2}))

t an g e n t y = 4 x^{2} - 3 x + 3, (1, 4)