integral of (1-2x^2+3x^3)

Lösung

\int (1 - 2 x^{2} + 3 x^{3}) d x

x - \frac{2 x ^{3}}{3} + \frac{3 x ^{4}}{4} + C

Schritte zur Lösung

\int 1 - 2 x^{2} + 3 x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int 2 x^{2} d x + \int 3 x^{3} d x

\int 1 d x = x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

= x - \frac{2 x ^{3}}{3} + \frac{3 x ^{4}}{4}

Füge eine Konstante zur Lösung hinzu

= x - \frac{2 x ^{3}}{3} + \frac{3 x ^{4}}{4} + C

l a pl a ce t r an s f or m e^{- t} \cdot sin (2 t)

f (x) = - sin (2 x) \cdot 2

\int \frac{x}{e ^{- x^{2}}} d x

\frac{\partial}{\partial x} (2 x ln (y))

\frac{d}{d x} (2 x^{2} - e^{x})