(\partial)/(\partial x)(x^2+y^2+(x+y)^2)

解答

\frac{\partial}{\partial x} (x^{2} + y^{2} + (x + y)^{2})

4 x + 2 y

求解步骤

\frac{\partial}{\partial x} (x^{2} + y^{2} + (x + y)^{2})

化简

x^{2} + y^{2} + (x + y)^{2} : 2 x^{2} + 2 x y + 2 y^{2}

= \frac{\partial}{\partial x} (2 x^{2} + 2 x y + 2 y^{2})

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 4 x + 2 y + 0

化简

= 4 x + 2 y

\frac{\partial}{\partial x} (\frac{1}{( 1 + e ^{- x} )})

\frac{d}{d x} (lo g_{10} ((x - 3)^{2}))

\int \frac{4 x ^{2} + 1}{2 x + 5} d x

\int e^{- \frac{3}{2} t} d t

d er i v a t i v e 3 x^{2} + 4 x + 8