(\partial)/(\partial x)(2x+1)

Lösung

\frac{\partial}{\partial x} (2 x + 1)

2

Schritte zur Lösung

\frac{\partial}{\partial x} (2 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (1) = 0

= 2 + 0

Vereinfache

= 2

\frac{\partial}{\partial z} (z cos (x z))

\int_{1}^{2} 2 r^{2} ln (r) d r

\int 0.75 e d k

\int \frac{1}{x} - 1 \frac{1}{x ^{2}} d x

in v erse l a pl a ce \frac{4}{s ( s ^{2} + s )}