derivative of 20t-1/2 {g}(t,xt^2)

Lösung

\frac{d}{d x} (20 t - \frac{1}{2} g (t, x) t^{2})

0 - \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

Schritte zur Lösung

\frac{d}{d x} (20 t - \frac{1}{2} g (t, x) t^{2})

Behandle

t

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20 t) - \frac{d}{d x} (\frac{1}{2} g (t, x) t^{2})

\frac{d}{d x} (20 t) = 0

\frac{d}{d x} (\frac{1}{2} g (t, x) t^{2}) = \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

= 0 - \frac{1}{2} t^{2} \frac{d}{d x} (g (t, x))

d er i v a t i v e lo g_{e} (x)

\frac{d}{d x} (x^{2} e^{- x} + (ln (x))^{2})

\int_{0}^{\frac{1}{2}} x ln (2 x) d x

\frac{d}{d x} (14 x^{\frac{1}{7}})

n = 0 \sum \infty \frac{( 3 x - 2 ) ^{n}}{n}