(\partial)/(\partial x)(-xyz+54)

解答

\frac{\partial}{\partial x} (- x yz + 54)

- yz

求解步骤

\frac{\partial}{\partial x} (- x yz + 54)

将

y, z

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x yz) + \frac{\partial}{\partial x} (54)

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (54) = 0

= - yz + 0

化简

= - yz

d er i v a t i v e 3 e^{x^{2}}

t an g e n t f (x) = \frac{1}{3} x^{3} - 14 x^{2} + 6 x + 1

\frac{d}{d x} (- x + \frac{8}{x} + 1)

y^{^{''}} + 10 y^{^{'}} + 24 y = 0

n = 1 \sum \infty 0.5