integral from 2 to 6 of (x-4)/(x+1)

Lösung

\int_{2}^{6} \frac{x - 4}{x + 1} d x

5 ln (3) - 5 ln (7) + 4

Dezimale

- 0.23648 \dots

Schritte zur Lösung

\int_{2}^{6} \frac{x - 4}{x + 1} d x

Multipliziere aus

\frac{x - 4}{x + 1} : \frac{x}{x + 1} - \frac{4}{x + 1}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} \frac{x}{x + 1} d x - \int_{2}^{6} \frac{4}{x + 1} d x

\int_{2}^{6} \frac{x}{x + 1} d x = 4 - ln (7) + ln (3)

\int_{2}^{6} \frac{4}{x + 1} d x = 4 (ln (7) - ln (3))

= 4 - ln (7) + ln (3) - 4 (ln (7) - ln (3))

Vereinfache

4 - ln (7) + ln (3) - 4 (ln (7) - ln (3)) : 5 ln (3) - 5 ln (7) + 4

= 5 ln (3) - 5 ln (7) + 4

\int x^{2} \cdot ln (6 x) d x

\frac{d}{d x} ((8 x + 15)^{12} (x^{3} + 7)^{13})

\int \frac{x - 9 x ^{2}}{x} d x

\frac{d y}{3 x + e ^{x}} = e^{- y} d x

e x p an d csc (x) (x + cot (x))