(\partial)/(\partial x)(2x^{0.5}+y)

解

\frac{\partial}{\partial x} (2 x^{0.5} + y)

\frac{1}{x ^{\frac{1}{2}}}

解答ステップ

\frac{\partial}{\partial x} (2 x^{0.5} + y)

y

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{0.5}) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x^{0.5}) = \frac{1}{x ^{0.5}}

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{x ^{0.5}} + 0

簡素化

= \frac{1}{x ^{\frac{1}{2}}}