(\partial)/(\partial x)(2x^2+3y^2-z^2)

Lösung

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} - z^{2})

4 x

Schritte zur Lösung

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} - z^{2})

Behandle

y, z

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (z^{2})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (z^{2}) = 0

= 4 x + 0 - 0

Vereinfache

= 4 x

t an g e n t y = 4 + x x, (1, 5)

x \to 2 lim (x^{4} - 8)

y^{^{''}} + y^{^{'}} - 6 y = 12 x - 50 sin (x)

\frac{d ^{2}}{d x ^{2}} (cos (7 x))

y^{^{'}} = 3 x (y + 4)^{2}