(dy)/(dx)=(2xy)/((x^2-y^2))

Lösung

\frac{d y}{d x} = \frac{2 x y}{( x ^{2} - y ^{2} )}

y = \frac{1 + - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}, y = \frac{1 - - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}

Schritte zur Lösung

\frac{d y}{d x} = \frac{2 x y}{( x ^{2} - y ^{2} )}

Solve using substitution:

y = \frac{1 + - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}, y = \frac{1 - - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}

y = \frac{1 + - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}, y = \frac{1 - - 4 e ^{2 c_{1}} x ^{2} + 1}{2 e ^{c_{1}}}

\int \frac{x}{x ^{2} + 6} d x

t an g e n t f (x) = 9 x^{2} - x^{3}, (2, 28)

\frac{d}{d x} (\frac{1}{3 x ^{5}})

d er i v a t i v e f (x) = (\frac{sin ( x )}{x})^{2}

\frac{\partial}{\partial y} (3 x + 2 x y^{2})