(dy)/(dx)=(8+x)^2

Lösung

\frac{d y}{d x} = (8 + x)^{2}

y = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = (8 + x)^{2}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = (8 + x)^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int (8 + x)^{2} d x

\int (8 + x)^{2} d x = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

y = 64 x + 8 x^{2} + \frac{x ^{3}}{3} + c_{1}

\int \frac{3 x ^{2} - x + 4}{x ^{3} + 2 x ^{2} + 6 x} d x

\frac{d}{d x} (\frac{13}{ln ( x )})

x \to \infty lim (\frac{e ^{2 x} + e ^{x}}{e ^{2 x} - 1} 1)

in v erse l a pl a ce \frac{1}{( s + 2 ) ( s - 1 ) ^{5}}

x \to \infty lim (2 - x^{2})