(dv}{dt}=\frac{49-10v)/5

解答

\frac{d v}{d t} = \frac{49 - 10 v}{5}

v = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{49}{10}

求解步骤

\frac{d v}{d t} = \frac{49 - 10 v}{5}

求解可分离方程:

v = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{49}{10}

v = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{49}{10}

\frac{d y}{d x} = y (y - 1)

a re a y = x, y = 3 x, y = - x + 4

(y + x y) d x = x d y

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} + 1})

t an g e n t 12 x^{2} + 3 x