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tangent y=2x^2+9x-7

解答

切线

y = 2 x^{2} + 9 x - 7

解答

y = (4 a_{0} + 9) x - 2 a_{0}^{2} - 7

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 2 a_{0}^{2} + 9 a_{0} - 7)

计算

y = 2 x^{2} + 9 x - 7

的斜率:

\frac{d y}{d x} = 4 x + 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0} + 9

找到斜率 m=

4 a_{0} + 9

且穿过

(a_{0}, 2 a_{0}^{2} + 9 a_{0} - 7)

的直线:

y = (4 a_{0} + 9) x - 2 a_{0}^{2} - 7

y = (4 a_{0} + 9) x - 2 a_{0}^{2} - 7

作图

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