extreme f(x)=xsqrt(x+8)

Lösung

extrempunkte

f (x) = x x + 8

Maximum (- 8, 0), Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

Schritte zur Lösung

f^{'} (x) = \frac{3 x + 16}{2 x + 8}

Intervalle finden:

Absteigend

: - 8 < x < - \frac{16}{3},

Ansteigend

: - \frac{16}{3} < x < \infty

Stecke

x = - 8

x x + 8 : 0

Maximum (- 8, 0)

Stecke

x = - \frac{16}{3}

x x + 8 : - \frac{32 2}{3 3}

Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

Maximum (- 8, 0), Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

e x t re m e f (x) = \frac{x + 2}{x ^{2} - 3 x - 10}

e x t re m e f (x) = (x^{2} - 2 x) e^{- x}

e x t re m e y = \frac{1}{3} x^{3} - 9 x^{2} + 72 x + 2

e x t re m e f (x) = (2^{2} + 3 x)^{2} - (2 x^{3} - 4 y^{2})

e x t re m e x^{2} - 10 x