extreme (x-2)^3+3

解答

极值点

(x - 2)^{3} + 3

鞍点 (2, 3)

求解步骤

f^{'} (x) = 3 x^{2} - 12 x + 12

Find intervals:

递增

: - \infty < x < 2,

递增

: 2 < x < \infty

将

x = 2

代入

(x - 2)^{3} + 3 : 3

鞍点 (2, 3)

e x t re m e f (x) = 68 x - x^{2}

e x t re m e f (x, y) = 4 x^{2} y - 2 x - y^{2}

e x t re m e x^{3} + x, - 1 \leq x \leq 2

e x t re m e f (x) = x^{2} - x y + y^{2} - 3 x + 3 y

e x t re m e f (x) = 5 - 3 x^{2}, - 5 \leq x \leq 1