extreme f(x)=x^3-2x-4x+4(0.3)

Lösung

extrempunkte

f (x) = x^{3} - 2 x - 4 x + 4 (0.3)

Maximum (- 2, 6.85685 \dots), Minimum (2, - 4.45685 \dots)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 6

Intervalle finden:

Ansteigend

: - \infty < x < - 2,

Absteigend

: - 2 < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = - 2

x^{3} - 2 x - 4 x + 40.3 : 6.85685 \dots

Maximum (- 2, 6.85685 \dots)

Stecke

x = 2

x^{3} - 2 x - 4 x + 40.3 : - 4.45685 \dots

Minimum (2, - 4.45685 \dots)

Maximum (- 2, 6.85685 \dots), Minimum (2, - 4.45685 \dots)

e x t re m e x^{2} + x^{- 2}

e x t re m e (x - 3)^{2} (x - 2)

e x t re m e f (x) = 6 x^{2} - 6 x + 9

e x t re m e f (x) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

e x t re m e - \frac{2}{4 x + x ^{2} - 2}